Question

1. set up the simulation with the kettle on high and the generator turbine in order to compare the efficiency of the two types of bulbs: the fluorescent bulb (curly one) and the incandescent bulb (rounded). as you do so, complete the table below to calculate the efficiency of each bulb by entering the number of energy squares you counted in each minute.

type of bulb	energy input (count the # of blue electrical energy blocks used in 1 minute)	energy output of light (count the # of yellow light energy blocks released in 1 minute)	percent efficiency (divide # of output by the # of input. then multiply the quotient by 100 to get the %) out ÷ in, then x100	energy loss to heat (count the # of red thermal energy blocks released in 1 minute)
incandescent (rounded)	49	29	59.18	17

what do you notice about the difference in the energy and output of these two bulbs?
which light bulb is more efficient? why?

Explanation:

Step1: Recall efficiency formula

Percent Efficiency = $\frac{\text{Energy Output}}{\text{Energy Input}}\times100$

Step2: Analyze fluorescent bulb

For the fluorescent bulb, Energy Input = 44, Energy Output = 42. Percent Efficiency = $\frac{42}{44}\times100\approx95.45\%$

Step3: Analyze incandescent bulb

For the incandescent bulb, Energy Input = 49, Energy Output = 29. Percent Efficiency = $\frac{29}{49}\times100\approx59.18\%$

Step4: Compare efficiencies

The fluorescent bulb has a higher percent - efficiency (95.45% > 59.18%). Also, the fluorescent bulb has less energy loss to heat (8 vs 17) compared to the incandescent bulb.

Answer:

The fluorescent (curly) bulb is more efficient. It has a higher percent - efficiency (95.45% compared to 59.18% for the incandescent bulb) and less energy loss to heat (8 energy squares lost to heat compared to 17 for the incandescent bulb).