Question

1. find the product: (4x^2 + 7)(4x^2 + 7) (4x^2 + 7)(4x^2 + 7) = |enter your next step here|

Explanation:

Step1: Recognize as square of binomial

$(4x^{2}+7)(4x^{2}+7)=(4x^{2}+7)^{2}$

Step2: Apply formula $(a + b)^2=a^{2}+2ab + b^{2}$

Here $a = 4x^{2}$ and $b = 7$. So, $(4x^{2})^{2}+2\times(4x^{2})\times7+7^{2}$

Step3: Simplify each term

$(4x^{2})^{2}=16x^{4}$, $2\times(4x^{2})\times7 = 56x^{2}$, $7^{2}=49$. Then we get $16x^{4}+56x^{2}+49$

Answer:

$16x^{4}+56x^{2} + 49$