QUESTION IMAGE
Question
- (196) distribute in the expression: (3x + 2y)(4x - 5y)
a) 12x² - 10y²
b) 7x - 7xy - 3y
c) 7x - 3y
d) 12x² - 7xy - 10y²
e) 12x² + 23xy + 10y²
- (141) solve: $\frac{5x}{4}+6=-3x$
a) $-\frac{24}{17}$
b) $-\frac{20}{19}$
c) $-\frac{17}{20}$
d) $-\frac{19}{17}$
Step1: Expand the first expression
Use FOIL method.
$$(3x + 2y)(4x - 5y)=3x\times4x+3x\times(- 5y)+2y\times4x+2y\times(-5y)$$
$$=12x^{2}-15xy + 8xy-10y^{2}$$
$$=12x^{2}-7xy - 10y^{2}$$
Step2: Solve the second - equation
First, get rid of the fraction. Multiply every term in the equation $\frac{5x}{4}+6=-3x$ by 4.
$$4\times\frac{5x}{4}+4\times6 = 4\times(-3x)$$
$$5x + 24=-12x$$
Then, add $12x$ to both sides.
$$5x+12x + 24=-12x+12x$$
$$17x+24 = 0$$
Subtract 24 from both sides.
$$17x+24 - 24=0 - 24$$
$$17x=-24$$
Divide both sides by 17.
$$x =-\frac{24}{17}$$
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- None of the given options are correct for the distribution problem.
- a. $-\frac{24}{17}$