Question

2-variable equations & inequalities solving simultaneous equations using substitution
solving simultaneous equations using substitution practice
complete this assessment to review what youve learned. it will not count toward your grade.

use the substitution method to solve the system $2x + 2y = 6$, $3x + 2y = 9$. (1 point)

check answer remaining attempts : 3

Explanation:

Step1: Isolate $x$ from first equation

Start with $2x + 2y = 6$. Divide all terms by 2:
$\frac{2x}{2} + \frac{2y}{2} = \frac{6}{2}$
Simplify to get $x + y = 3$, then rearrange:
$x = 3 - y$

Step2: Substitute $x$ into second equation

Substitute $x = 3 - y$ into $3x + 2y = 9$:
$3(3 - y) + 2y = 9$
Expand and simplify:
$9 - 3y + 2y = 9$
$9 - y = 9$

Step3: Solve for $y$

Rearrange to isolate $y$:
$-y = 9 - 9$
$-y = 0$
$y = 0$

Step4: Substitute $y$ back for $x$

Use $x = 3 - y$, substitute $y=0$:
$x = 3 - 0$
$x = 3$

Answer:

$x=3$, $y=0$ (or the ordered pair $(3, 0)$)