Question

20 candies are in a bag. 4 of them are red. what is the probability of drawing 2 red candies if the first one is placed back in the bag before the second draw? round your answer to the nearest hundredth.

Explanation:

Step1: Calculate probability of first draw

The probability of drawing a red candy on the first draw is the number of red candies divided by the total number of candies. There are 4 red candies and 20 total candies, so the probability $P_1=\frac{4}{20}= 0.2$.

Step2: Calculate probability of second draw

Since the first candy is placed back, the situation for the second draw is the same as the first. The probability of drawing a red candy on the second draw $P_2=\frac{4}{20}=0.2$.

Step3: Calculate probability of both events

For independent events (since the first candy is replaced), the probability of both events occurring is the product of their individual probabilities. So $P = P_1\times P_2=0.2\times0.2 = 0.04$.

Answer:

$0.04$