Question

20 a cart’s initial velocity is +3.0 meters per second. what is its final velocity after accelerating at a rate of 1.5 m/s² for 8.0 seconds? f 9 m/s g 15 m/s h 36 m/s j 72 m/s

Explanation:

Step1: Recall the kinematic equation

The kinematic equation for final velocity \( v_f \) is \( v_f = v_i + at \), where \( v_i \) is the initial velocity, \( a \) is the acceleration, and \( t \) is the time.

Step2: Identify the given values

We have \( v_i = 3.0 \, \text{m/s} \), \( a = 1.5 \, \text{m/s}^2 \), and \( t = 8.0 \, \text{s} \).

Step3: Substitute the values into the equation

Substitute the values into \( v_f = v_i + at \):
\( v_f = 3.0 + (1.5)(8.0) \)
First, calculate \( (1.5)(8.0) = 12.0 \)
Then, \( v_f = 3.0 + 12.0 = 15.0 \, \text{m/s} \)

Answer:

G 15 m/s