QUESTION IMAGE
Question
- proving a theorem complete the two - column proof for the congruent supplements theorem. then write a paragraph proof. example 3
given ∠1 and ∠2 are supplementary.
∠3 and ∠4 are supplementary.
∠1 ≅ ∠4
prove ∠2 ≅ ∠3
statements | reasons
- ∠1 and ∠2 are supplementary, ∠3 and ∠4 are supplementary, ∠1 ≅ ∠4 | 1. given
- m∠1 + m∠2 = 180°, m∠3 + m∠4 = 180° | 2. ______
- ______ = m∠3 + m∠4 | 3. transitive property of equality
- m∠1 = m∠4 | 4. definition of congruent angles
- m∠1 + m∠2 = ______ | 5. substitution property of equality
- m∠2 = m∠3 | 6. ______
- ____ | 7. ____
- writing explain why you do not use inductive reasoning when writing a proof.
. how do you see it?
consider the two - column proof. what is the writer trying to prove?
given ∠1 ≅ ∠2
∠1 and ∠2 are supplementary.
prove ________
Problem 20 (Two - column proof for Congruent Supplements Theorem)
Step 1: Reason for Statement 2
The definition of supplementary angles states that if two angles are supplementary, the sum of their measures is \(180^{\circ}\). So for \(\angle1\) and \(\angle2\) being supplementary, \(m\angle1 + m\angle2=180^{\circ}\), and for \(\angle3\) and \(\angle4\) being supplementary, \(m\angle3 + m\angle4 = 180^{\circ}\). So the reason for statement 2 is "Definition of supplementary angles".
Step 2: Statement 3
From step 2, we have \(m\angle1 + m\angle2=180^{\circ}\) and \(m\angle3 + m\angle4 = 180^{\circ}\). By the Transitive Property of Equality (since both equal \(180^{\circ}\)), we can say \(m\angle1 + m\angle2=m\angle3 + m\angle4\).
Step 3: Statement 5
We know from step 2 that \(m\angle3 + m\angle4 = 180^{\circ}\), and from the Substitution Property of Equality (since \(m\angle1 + m\angle2=m\angle3 + m\angle4\)), we substitute \(m\angle3 + m\angle4\) with \(180^{\circ}\) in the equation \(m\angle1 + m\angle2=m\angle3 + m\angle4\) to get \(m\angle1 + m\angle2 = 180^{\circ}\) (wait, actually, we can also use the fact that \(m\angle1=m\angle4\) from step 4. Let's correct this. Since \(m\angle1 + m\angle2=180^{\circ}\) and \(m\angle1=m\angle4\), by substitution, we can also look at the equation \(m\angle1 + m\angle2=m\angle3 + m\angle4\). Substitute \(m\angle1\) with \(m\angle4\) in \(m\angle1 + m\angle2\), we get \(m\angle4 + m\angle2\). But also, \(m\angle3 + m\angle4=180^{\circ}\) and \(m\angle1 + m\angle2 = 180^{\circ}\). Since \(m\angle1=m\angle4\), then \(m\angle1 + m\angle2=m\angle4 + m\angle2=180^{\circ}\) and \(m\angle3 + m\angle4 = 180^{\circ}\). So \(m\angle4 + m\angle2=m\angle3 + m\angle4\). Then, by Subtraction Property of Equality (subtract \(m\angle4\) from both sides), we get \(m\angle2=m\angle3\). But let's follow the two - column proof:
- Statement 5: Since \(m\angle1 + m\angle2 = 180^{\circ}\) (from step 2) and \(m\angle3 + m\angle4=180^{\circ}\) (from step 2) and \(m\angle1=m\angle4\) (from step 4), by substitution, \(m\angle1 + m\angle2=m\angle3 + m\angle1\) (substituting \(m\angle4\) with \(m\angle1\) in \(m\angle3 + m\angle4\)). Wait, no, the correct substitution is: from \(m\angle1 + m\angle2=180^{\circ}\) and \(m\angle3 + m\angle4 = 180^{\circ}\) and \(m\angle1=m\angle4\), so \(m\angle1 + m\angle2=m\angle3 + m\angle1\) (because \(m\angle4 = m\angle1\)). Then, by Subtraction Property of Equality (subtract \(m\angle1\) from both sides), we get \(m\angle2=m\angle3\). But in the given two - column proof, statement 5 is \(m\angle1 + m\angle2=\underline{180^{\circ}}\) (wait, no, let's re - examine the table:
Looking at the table:
- Statement 2: \(m\angle1 + m\angle2 = 180^{\circ}\), \(m\angle3 + m\angle4=180^{\circ}\)
- Statement 3: \(\underline{m\angle1 + m\angle2}=m\angle3 + m\angle4\) (by Transitive Property, since both equal \(180^{\circ}\))
- Statement 4: \(m\angle1=m\angle4\) (Definition of congruent angles, since \(\angle1\cong\angle4\))
- Statement 5: \(m\angle1 + m\angle2=\underline{m\angle3 + m\angle1}\) (by Substitution Property, substituting \(m\angle4\) with \(m\angle1\) in \(m\angle3 + m\angle4\))
- Statement 6: \(m\angle2=m\angle3\) (by Subtraction Property of Equality, subtract \(m\angle1\) from both sides of \(m\angle1 + m\angle2=m\angle3 + m\angle1\))
- Statement 7: \(\angle2\cong\angle3\) (by Definition of congruent angles, since \(m\angle2 = m\angle3\))
And the reasons:
- Reason 2: Definition of supplementary angles
- Reason 6: Subtraction Property of Equality
- Reason 7: Defin…
Inductive reasoning is based on observing patterns in specific cases (e.g., looking at several examples and generalizing). However, a mathematical proof requires a general, deductive argument that shows a statement is true for all cases (not just observed ones). For example, if we use inductive reasoning to prove "all triangles have sum of interior angles \(180^{\circ}\)", we might measure a few triangles, but this doesn't prove it for every triangle. A deductive proof (using postulates, theorems) shows it for any triangle. So in writing a proof, we need a logical, deductive chain (using definitions, postulates, theorems) that is valid for all instances, not just observed ones.
- From \(\angle1\cong\angle2\), \(m\angle1 = m\angle2\) (def. of congruent angles).
- From \(\angle1\) and \(\angle2\) supplementary, \(m\angle1 + m\angle2 = 180^{\circ}\) (def. of supplementary angles).
- Substitute \(m\angle2\) with \(m\angle1\): \(2m\angle1=180^{\circ}\Rightarrow m\angle1 = 90^{\circ}\), so \(m\angle2 = 90^{\circ}\). Thus, \(\angle1\) and \(\angle2\) are right angles.
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Inductive reasoning generalizes from specific cases (patterns in examples) but doesn't guarantee truth for all cases. Proofs need deductive reasoning (using definitions, postulates, theorems) to show a statement is true for all instances, not just observed ones.
"How Do You See It?" Problem
Given \(\angle1\cong\angle2\) and \(\angle1\) and \(\angle2\) are supplementary. Let's find what to prove.
If \(\angle1\cong\angle2\), then \(m\angle1 = m\angle2\) (Definition of congruent angles). If \(\angle1\) and \(\angle2\) are supplementary, then \(m\angle1 + m\angle2=180^{\circ}\) (Definition of supplementary angles). Substitute \(m\angle2\) with \(m\angle1\) (since \(m\angle1 = m\angle2\)): \(m\angle1+m\angle1 = 180^{\circ}\), \(2m\angle1 = 180^{\circ}\), \(m\angle1 = 90^{\circ}\). So \(m\angle2=90^{\circ}\) too. So \(\angle1\) and \(\angle2\) are right angles. So we need to prove that \(\angle1\) and \(\angle2\) are right angles (or \(\angle1\cong90^{\circ}\), \(\angle2\cong90^{\circ}\)).