Question

1. what is the diagonal of the front side of the tank if the length is 120\, the width is 38\ and the height is 130\?

Explanation:

Step1: Identify the sides of the front - side rectangle

The front - side of the tank has length \(l = 120\) inches and height \(h=130\) inches. The width is not relevant for the front - side diagonal.

Step2: Apply the Pythagorean theorem

For a right - triangle with sides \(a\) and \(b\) and hypotenuse \(c\), \(c=\sqrt{a^{2}+b^{2}}\). Here, \(a = 120\) and \(b = 130\). So, \(c=\sqrt{120^{2}+130^{2}}\).
First, calculate \(120^{2}=14400\) and \(130^{2}=16900\). Then \(120^{2}+130^{2}=14400 + 16900=31300\). So, \(c=\sqrt{31300}\approx176.92\) inches.

Answer:

Approximately \(176.92\) inches