Question

1. ann works at a store in the mall and earns a wage of $8 an hour. she earns $10 an hour if she works on the weekends. last week she worked 24 hours during the week and 16 hours on the weekend. how much did ann earn last week?
2. select all the correct comparisons.

$\frac{10}{12} > \frac{5}{6}$
$\frac{6}{8} = \frac{3}{4}$
$\frac{1}{8} > \frac{1}{10}$
$\frac{9}{10} < \frac{4}{5}$
$\frac{1}{100} > \frac{1}{10}$

Explanation:

Question 24

Step1: Calculate weekday earnings

Weekday wage is $8 per hour, worked 24 hours. So earnings = \( 8 \times 24 \)
\( 8 \times 24 = 192 \)

Step2: Calculate weekend earnings

Weekend wage is $10 per hour, worked 16 hours. So earnings = \( 10 \times 16 \)
\( 10 \times 16 = 160 \)

Step3: Total earnings

Add weekday and weekend earnings: \( 192 + 160 \)
\( 192 + 160 = 352 \)

• For \(\frac{10}{12} > \frac{5}{6}\): Simplify \(\frac{5}{6} = \frac{10}{12}\), so \(\frac{10}{12} = \frac{5}{6}\), not greater.
• For \(\frac{6}{8} = \frac{3}{4}\): Simplify \(\frac{6}{8}\) by dividing numerator and denominator by 2, get \(\frac{3}{4}\), so equal.
• For \(\frac{1}{8} > \frac{1}{10}\): For unit fractions, smaller denominator means larger value. 8 < 10, so \(\frac{1}{8} > \frac{1}{10}\).
• For \(\frac{9}{10} < \frac{4}{5}\): Simplify \(\frac{4}{5} = \frac{8}{10}\), \(\frac{9}{10} > \frac{8}{10}\), so false.
• For \(\frac{1}{100} > \frac{1}{10}\): Smaller denominator (10 < 100) means \(\frac{1}{10} > \frac{1}{100}\), so false.

Answer:

\$352

Question 26