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Question
- given: r is the mid - point of qt, qs≅ts. prove: ∠rqs≅∠rts. statement: r is the mid - point of qt, qs≅ts, qr≅tr, rs≅rs, △rsq≅△rts, ∠rqs≅∠rts. reason: given, given, def of midpoint, reflexive property, sss, cpctc
Step1: Recall mid - point definition
Since R is the mid - point of QT, by the definition of a mid - point, we have QR = TR.
Step2: Use given side - equality
We are given that QS = TS and RS = RS (reflexive property).
Step3: Apply SSS congruence criterion
In \(\triangle RSQ\) and \(\triangle RTS\), we have QR = TR, QS = TS, and RS = RS. So, \(\triangle RSQ\cong\triangle RTS\) by the Side - Side - Side (SSS) congruence criterion.
Step4: Use CPCTC
Since \(\triangle RSQ\cong\triangle RTS\), corresponding parts of congruent triangles are congruent (CPCTC). So, \(\angle RQS=\angle RTS\).
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- Statement: R is the mid - point of QT; Reason: Given
- Statement: QS = TS; Reason: Given
- Statement: RS = RS; Reason: Reflexive Property
- Statement: QR = TR; Reason: Definition of mid - point
- Statement: \(\triangle RSQ\cong\triangle RTS\); Reason: SSS
- Statement: \(\angle RQS=\angle RTS\); Reason: CPCTC