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Question
(b + 3)(b² + 2b + 1) options: b³+5b²+7b+3; b³+6b²+6b+3; 4b³+8b²+3b; 3b³+6b²+3b
Step1: Distribute $b$ to the quadratic
$b(b^2 + 2b + 1) = b^3 + 2b^2 + b$
Step2: Distribute $3$ to the quadratic
$3(b^2 + 2b + 1) = 3b^2 + 6b + 3$
Step3: Combine like terms
$(b^3 + 2b^2 + b) + (3b^2 + 6b + 3) = b^3 + (2b^2+3b^2) + (b+6b) + 3$
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$b^3+5b^2+7b+3$