Question

(2x - 5) + \left(\frac{1}{3}x + 2\
ight) + \left(\frac{3}{4}x - 6\
ight)

Explanation:

Step1: Remove parentheses

$2x - 5 + \frac{1}{3}x + 2 + \frac{3}{4}x - 6$

Step2: Group like terms

$(2x + \frac{1}{3}x + \frac{3}{4}x) + (-5 + 2 - 6)$

Step3: Combine x-terms

Find common denominator 12:
$2x = \frac{24}{12}x$, $\frac{1}{3}x = \frac{4}{12}x$, $\frac{3}{4}x = \frac{9}{12}x$
$\frac{24}{12}x + \frac{4}{12}x + \frac{9}{12}x = \frac{37}{12}x$

Step4: Combine constant terms

$-5 + 2 - 6 = -9$

Answer:

$\frac{37}{12}x - 9$