Question

1. determine the torque on a 0.5 m long wrench if a force of 230 n is applied at an angle of 80°.

226.5 n·m
115 n·m
550 n·m
113.3 n·m

Explanation:

Step1: Recall torque formula

$\tau = rF\sin\theta$

Step2: Substitute given values

$r=0.5\ \text{m}$, $F=230\ \text{N}$, $\theta=80^\circ$
$\tau = 0.5 \times 230 \times \sin(80^\circ)$

Step3: Calculate the result

$\sin(80^\circ) \approx 0.9848$
$\tau \approx 0.5 \times 230 \times 0.9848 = 226.5\ \text{N·m}$

Answer:

A. 226.5 N·m