Question

1. sports the distance between each base on a baseball infield is 90 feet. the third baseman throws a ball from third base to point p. to the nearest foot, how far did the player throw the ball?

Explanation:

Step1: Consider the right - angled triangle

The baseball infield is a square with side length 90 feet. We can consider a right - angled triangle to find the distance from third base to point P. The horizontal distance from third base to the line of point P is 90 feet and the vertical distance (along the line from first base to point P) is 30 feet.

Step2: Apply the Pythagorean theorem

The Pythagorean theorem for a right - angled triangle with legs \(a\) and \(b\) and hypotenuse \(c\) is \(c=\sqrt{a^{2}+b^{2}}\). Here, \(a = 90\) and \(b=30\). So \(c=\sqrt{90^{2}+30^{2}}=\sqrt{8100 + 900}=\sqrt{9000}\).

Step3: Calculate the value

\(\sqrt{9000}\approx95\) (rounded to the nearest foot).

Answer:

95