Question

1. determine the rotational inertia of a cylinder with a mass of 25 kg and a radius of 1 m.

25 kg·m²
50 kg·m²
6.25 kg·m²
12.5 kg·m²

Explanation:

Step1: Recall cylinder inertia formula

The rotational inertia (moment of inertia) for a solid cylinder rotating about its central axis is $I = \frac{1}{2}MR^2$, where $M$ is mass, $R$ is radius.

Step2: Substitute given values

$M=25\ \text{kg}$, $R=1\ \text{m}$. Substitute into formula:
$I = \frac{1}{2} \times 25 \times (1)^2$

Step3: Calculate the result

$I = \frac{25}{2} = 12.5\ \text{kg·m}^2$

Answer:

12.5 kg·m²