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35 n the person experiences a reaction force of +35 n. what is the acce…

Question

35 n
the person experiences a
reaction force of +35 n.
what is the acceleration
of the person?
remember: f = ma
105 kg
-2.5 m/s² +0.33 m/s²
-0.33 m/s² +2.5 m/s²

Explanation:

Step1: Recall the formula \( F = ma \)

We know that \( F = ma \), so we can solve for acceleration \( a \) by rearranging the formula to \( a=\frac{F}{m} \).

Step2: Identify the values of \( F \) and \( m \)

The force \( F \) is \( +35 \, \text{N} \) and the mass \( m \) of the person (on the skateboard) is \( 105 \, \text{kg} \).

Step3: Substitute the values into the formula

Substitute \( F = 35 \, \text{N} \) and \( m = 105 \, \text{kg} \) into \( a=\frac{F}{m} \):
\[
a=\frac{35}{105}=\frac{1}{3}\approx + 0.33 \, \text{m/s}^2
\]

Answer:

\( +0.33 \, \text{m/s}^2 \) (corresponding to the option: +0.33 m/s²)