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Question
- $-3sqrt{192}$
- $6sqrt{96}$
Problem 38: $-3\sqrt{192}$
Step1: Factor out perfect square
$192 = 64 \times 3$, so $\sqrt{192} = \sqrt{64 \times 3}$
Step2: Simplify square root
$\sqrt{64 \times 3} = \sqrt{64} \times \sqrt{3} = 8\sqrt{3}$
Step3: Multiply by coefficient
$-3 \times 8\sqrt{3} = -24\sqrt{3}$
Problem 40: $6\sqrt{96}$
Step1: Factor out perfect square
$96 = 16 \times 6$, so $\sqrt{96} = \sqrt{16 \times 6}$
Step2: Simplify square root
$\sqrt{16 \times 6} = \sqrt{16} \times \sqrt{6} = 4\sqrt{6}$
Step3: Multiply by coefficient
$6 \times 4\sqrt{6} = 24\sqrt{6}$
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- $-24\sqrt{3}$
- $24\sqrt{6}$