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40÷(72÷9)=8

Question

40÷(72÷9)=8

Explanation:

Step1: Calculate inside the parentheses

First, we solve the operation inside the parentheses, which is \(72 \div 9\).
\(72 \div 9 = 8\)

Step2: Perform the division

Now we have the expression \(40 \div (72 \div 9)\) which simplifies to \(40 \div 8\) after Step 1.
\(40 \div 8 = 5\)

Wait, but the original problem shows \(40\div(72\div9)=8\), which is incorrect. Let's re - check the calculation:

Step1: Solve the parenthesis

As per the order of operations (PEMDAS/BODMAS), we first calculate the expression inside the parentheses. For \(72\div9\), we know that \(9\times8 = 72\), so \(72\div9=8\).

Step2: Do the outer division

Now we have to calculate \(40\div(72\div9)=40\div8\). Since \(8\times5 = 40\), \(40\div8 = 5\). So the correct result of \(40\div(72\div9)\) is \(5\), not \(8\).

Answer:

The correct result of \(40\div(72\div9)\) is \(5\) (the given equation \(40\div(72\div9)=8\) is wrong).