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Question
45–49. sketching graphs of functions sketch the graph of a function with the given properties. you do not need to find a formula for the function.
- ( f(2) = 1, limlimits_{x \to 2} f(x) = 3 )
- ( f(1) = 0, f(2) = 4, f(3) = 6, limlimits_{x \to 2^-} f(x) = -3, limlimits_{x \to 2^+} f(x) = 5 )
- ( g(1) = 0, g(2) = 1, g(3) = -2, limlimits_{x \to 2} g(x) = 0, limlimits_{x \to 3^-} g(x) = -1, limlimits_{x \to 3^+} g(x) = -2 )
To solve these problems of sketching the graphs of functions with given properties, we analyze each problem based on the definitions of function values and limits.
Problem 45
We need to sketch a function \( f(x) \) such that \( f(2) = 1 \) and \( \lim_{x \to 2} f(x) = 3 \).
Step 1: Understand the function value at \( x = 2 \)
The function value at \( x = 2 \) is \( f(2) = 1 \). This means the point \( (2, 1) \) is on the graph of the function.
Step 2: Understand the limit as \( x \to 2 \)
The limit \( \lim_{x \to 2} f(x) = 3 \) means that as \( x \) approaches 2 from both the left and the right, the function values approach 3. So, we can draw a "hole" or an open circle at \( (2, 3) \) to represent the limit, and a closed dot at \( (2, 1) \) to represent the function value at \( x = 2 \). The graph can be constructed such that as \( x \) approaches 2 from either side, the function approaches 3, but at \( x = 2 \), the function has a value of 1.
Problem 46
We need to sketch a function \( f(x) \) such that \( f(1) = 0 \), \( f(2) = 4 \), \( f(3) = 6 \), \( \lim_{x \to 2^-} f(x) = -3 \), and \( \lim_{x \to 2^+} f(x) = 5 \).
Step 1: Plot the function values
- At \( x = 1 \), the function value is \( f(1) = 0 \), so we plot the point \( (1, 0) \).
- At \( x = 2 \), the function value is \( f(2) = 4 \), so we plot the point \( (2, 4) \).
- At \( x = 3 \), the function value is \( f(3) = 6 \), so we plot the point \( (3, 6) \).
Step 2: Analyze the left - hand limit as \( x \to 2 \)
The left - hand limit \( \lim_{x \to 2^-} f(x) = -3 \) means that as \( x \) approaches 2 from the left (values of \( x \) less than 2), the function values approach - 3. So, we can draw a curve approaching an open circle at \( (2, - 3) \) from the left.
Step 3: Analyze the right - hand limit as \( x \to 2 \)
The right - hand limit \( \lim_{x \to 2^+} f(x) = 5 \) means that as \( x \) approaches 2 from the right (values of \( x \) greater than 2), the function values approach 5. So, we can draw a curve approaching an open circle at \( (2, 5) \) from the right. And we have a closed dot at \( (2, 4) \) for the function value at \( x = 2 \).
Problem 47
We need to sketch a function \( g(x) \) such that \( g(1) = 0 \), \( g(2) = 1 \), \( g(3) = - 2 \), \( \lim_{x \to 2} g(x) = 0 \), \( \lim_{x \to 3^-} g(x) = - 1 \), and \( \lim_{x \to 3^+} g(x) = - 2 \).
Step 1: Plot the function values
- At \( x = 1 \), the function value is \( g(1) = 0 \), so we plot the point \( (1, 0) \).
- At \( x = 2 \), the function value is \( g(2) = 1 \), so we plot the point \( (2, 1) \).
- At \( x = 3 \), the function value is \( g(3) = - 2 \), so we plot the point \( (3, - 2) \).
Step 2: Analyze the limit as \( x \to 2 \)
The limit \( \lim_{x \to 2} g(x) = 0 \) means that as \( x \) approaches 2 from both the left and the right, the function values approach 0. So, we draw a curve approaching an open circle at \( (2, 0) \) from both sides, and we have a closed dot at \( (2, 1) \) for the function value at \( x = 2 \).
Step 3: Analyze the left - hand limit as \( x \to 3 \)
The left - hand limit \( \lim_{x \to 3^-} g(x) = - 1 \) means that as \( x \) approaches 3 from the left (values of \( x \) less than 3), the function values approach - 1. So, we draw a curve approaching an open circle at \( (3, - 1) \) from the left.
Step 4: Analyze the right - hand limit as \( x \to 3 \)
The right - hand limit \( \lim_{x \to 3^+} g(x) = - 2 \) means that as \( x \) approaches 3 from the right (values of \( x \) greater than 3), the func…
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for Problem 45
- Plot \( (2,1) \) (closed dot).
- Draw curves approaching \( (2,3) \) (open circle) as \( x \to 2 \) from left and right.