Question

49x¹³ - 9x

Explanation:

Step1: Rewrite terms with exponents

$49x^{13} = (7^2)x^{13} = 7^2x^{12} \cdot x = (7x^6)^2 \cdot x$, $9x = 3^2x$

Step2: Factor out common term

Factor out $x$ from the expression:
$x(49x^{12} - 9)$

Step3: Recognize difference of squares

Rewrite $49x^{12}-9$ as $(7x^6)^2 - 3^2$, then apply $a^2-b^2=(a-b)(a+b)$:
$x(7x^6 - 3)(7x^6 + 3)$

Answer:

$x(7x^6 - 3)(7x^6 + 3)$