Question

1. 4x - 7 = 13
2. 3t - 2 = 19

solve
3t - 2 = 19
+2 = +2
3t = 21
(3t)/3 = 21/3
t = 7
check
3t - 2 = 19
3(7) - 2 = 19
21 - 2 = 19
19 = 19

1. 16 = 8 + 4a

Explanation:

Step1: Solve for $x$ (Q4)

Add 7 to both sides:
$4x - 7 + 7 = 13 + 7$
$4x = 20$
Divide by 4:
$\frac{4x}{4} = \frac{20}{4}$
$x = 5$

Step2: Correctly solve for $t$ (Q6)

Add 2 to both sides:
$3t - 2 + 2 = 19 + 2$
$3t = 21$
Divide by 3:
$\frac{3t}{3} = \frac{21}{3}$
$t = 7$
Check: Substitute $t=7$:
$3(7) - 2 = 21 - 2 = 19$

Step3: Solve for $a$ (Q8)

Subtract 8 from both sides:
$16 - 8 = 8 + 4a - 8$
$8 = 4a$
Divide by 4:
$\frac{8}{4} = \frac{4a}{4}$
$a = 2$

Answer:

1. For $4x - 7 = 13$: $x = 5$
2. For $3t - 2 = 19$: $t = 7$ (corrected solution)
3. For $16 = 8 + 4a$: $a = 2$