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(x + 4)(x + 2)\ x²+4x+8\ x²+8x+8\ x²+8x+6\ x²+6x+8

Question

(x + 4)(x + 2)\
x²+4x+8\
x²+8x+8\
x²+8x+6\
x²+6x+8

Explanation:

Step1: Apply FOIL method

$(x+4)(x+2) = x\cdot x + x\cdot2 + 4\cdot x + 4\cdot2$

Step2: Calculate each term

$= x^2 + 2x + 4x + 8$

Step3: Combine like terms

$= x^2 + (2x+4x) + 8 = x^2 + 6x + 8$

Answer:

D. $x^2+6x+8$