Question

if a 50 n block experiences a force of kinetic friction of 11 n from the surface of a table, then what is the coefficient of kinetic friction ($mu_{k}$) between the block and the table?

Explanation:

Step1: Recall friction formula

The formula for kinetic - friction is $F_k=\mu_kN$, where $F_k$ is the force of kinetic friction, $\mu_k$ is the coefficient of kinetic friction, and $N$ is the normal force.

Step2: Rearrange the formula to solve for $\mu_k$

We can rewrite the formula as $\mu_k=\frac{F_k}{N}$.

Step3: Substitute given values

Given that $F_k = 11\ N$ and $N = 50\ N$, we substitute these values into the formula: $\mu_k=\frac{11}{50}=0.22$.

Answer:

$0.22$