Question

1. \

$$\begin{cases} 5x + 3y = 15 \\\\ x - 6y = 3 \\end{cases}$$

Explanation:

Step1: Isolate $x$ from second equation

From $x - 6y = 3$, we get $x = 6y + 3$.

Step2: Substitute $x$ into first equation

Substitute $x=6y+3$ into $5x + 3y = 15$:
$$5(6y + 3) + 3y = 15$$
Expand and simplify:
$$30y + 15 + 3y = 15$$
$$33y + 15 = 15$$

Step3: Solve for $y$

Subtract 15 from both sides:
$$33y = 0$$
$$y = 0$$

Step4: Solve for $x$

Substitute $y=0$ into $x = 6y + 3$:
$$x = 6(0) + 3 = 3$$

Answer:

$x=3$, $y=0$