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80 - kg person sits 3.0 m from the center of a horizontally rotating pl…

Question

80 - kg person sits 3.0 m from the center of a horizontally rotating platform with a tangential speed of 4.0 m/s. what is the angular momentum of the person? express your answer in kilograms - meters squared per second. l = kg·m²/s

Explanation:

Step1: Recall angular - momentum formula

The formula for angular momentum is $L = mvr$, where $m$ is the mass, $v$ is the tangential speed, and $r$ is the distance from the axis of rotation.

Step2: Identify given values

Given $m = 80\ kg$, $v=4.0\ m/s$, and $r = 3.0\ m$.

Step3: Substitute values into formula

$L=(80\ kg)\times(4.0\ m/s)\times(3.0\ m)$
$L = 960\ kg\cdot m^{2}/s$

Answer:

$960$