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Question
ab is tangent to ⊙c at point b and ad is tangent to ⊙c at point d. what is m∠a? 34° 62° 56° 124°
Step1: Recall tangent - radius property
A tangent to a circle is perpendicular to the radius at the point of tangency. So, \(\angle ABC = 90^{\circ}\) and \(\angle ADC=90^{\circ}\).
Step2: Use the sum of interior angles of a quadrilateral
The sum of the interior angles of a quadrilateral is \(360^{\circ}\). In quadrilateral \(ABCD\) (where \(C\) is the center of the circle), we know \(\angle ABC = 90^{\circ}\), \(\angle ADC = 90^{\circ}\), and \(\angle BCD=124^{\circ}\). Let \(\angle A=x\). Then, \(x + 90^{\circ}+124^{\circ}+90^{\circ}=360^{\circ}\).
Step3: Solve for \(x\)
First, simplify the left - hand side of the equation: \(x+90 + 124+90=x + 304\). Then, set up the equation \(x + 304=360\). Subtract \(304\) from both sides: \(x=360 - 304 = 56^{\circ}\).
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\(56^{\circ}\)