Question

abcd is a square. given that the measure of ∠edc = 62°, which expression below could be used to find the measure of ∠ade? 90 - (2 × 62) 90 + (62 - 10) 90 - 62 62 + 2

Explanation:

Step1: Recall angle property of square

In square ABCD, $\angle ADC = 90^{\circ}$.

Step2: Express $\angle ADE$ in terms of known angles

$\angle ADE+\angle EDC=\angle ADC$. So $\angle ADE=\angle ADC - \angle EDC$. Since $\angle ADC = 90^{\circ}$ and $\angle EDC = 62^{\circ}$, then $\angle ADE=90 - 62$.

Answer:

$90 - 62$