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Question
abcd is a square. given that the measure of ∠edc = 70°, which expression below could be used to find the measure of ∠ade? 90+(70 + 10) 90 - 70
Step1: Recall angle - property of a square
In square \(ABCD\), \(\angle ADC = 90^{\circ}\), and \(\angle ADC=\angle ADE+\angle EDC\).
Step2: Solve for \(\angle ADE\)
We know \(\angle ADC = 90^{\circ}\) and \(\angle EDC = 70^{\circ}\). So, \(\angle ADE=\angle ADC-\angle EDC\). Substituting the values, we get \(\angle ADE = 90 - 70\).
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\(90 - 70\)