Question

2.4 acceleration

1. a cheetah can accelerate from rest to a speed of 30.0 m/s in 7.00 s. what is its acceleration?
2. professional application

Explanation:

Step1: Recall acceleration formula

The formula for acceleration is $a=\frac{v - u}{t}$, where $v$ is final velocity, $u$ is initial velocity and $t$ is time.

Step2: Identify given values

The cheetah starts from rest, so $u = 0\ m/s$, $v=30.0\ m/s$ and $t = 7.00\ s$.

Step3: Substitute values into formula

$a=\frac{30.0 - 0}{7.00}=\frac{30.0}{7.00}\ m/s^{2}\approx4.29\ m/s^{2}$

Answer:

$4.29\ m/s^{2}$