Question

activity 1
solve by multiplying across. do not simplify the answers.

1. \\(\frac{2}{3} \cdot \frac{7}{9}\\) 2. \\(\frac{1}{6} \cdot \frac{3}{7}\\) 3. \\(\frac{1}{8} \cdot \frac{9}{1}\\)
2. \\(\frac{1}{9} \cdot \frac{3}{4}\\) 5. \\(\frac{5}{6} \cdot \frac{3}{6}\\) 6. \\(\frac{1}{7} \cdot \frac{4}{1}\\)

activity 2

Explanation:

Step1: Multiply numerators and denominators

$\frac{2}{3} \cdot \frac{7}{9} = \frac{2 \times 7}{3 \times 9}$

Step2: Calculate the products

$\frac{14}{27}$

Step1: Multiply numerators and denominators

$\frac{1}{6} \cdot \frac{3}{7} = \frac{1 \times 3}{6 \times 7}$

Step2: Calculate the products

$\frac{3}{42}$

Step1: Multiply numerators and denominators

$\frac{1}{8} \cdot \frac{9}{1} = \frac{1 \times 9}{8 \times 1}$

Step2: Calculate the products

$\frac{9}{8}$

Step1: Multiply numerators and denominators

$\frac{1}{9} \cdot \frac{3}{4} = \frac{1 \times 3}{9 \times 4}$

Step2: Calculate the products

$\frac{3}{36}$

Step1: Multiply numerators and denominators

$\frac{5}{6} \cdot \frac{3}{6} = \frac{5 \times 3}{6 \times 6}$

Step2: Calculate the products

$\frac{15}{36}$

Step1: Multiply numerators and denominators

$\frac{1}{7} \cdot \frac{4}{1} = \frac{1 \times 4}{7 \times 1}$

Step2: Calculate the products

$\frac{4}{7}$

Answer:

1. $\frac{14}{27}$
2. $\frac{3}{42}$
3. $\frac{9}{8}$
4. $\frac{3}{36}$
5. $\frac{15}{36}$
6. $\frac{4}{7}$