Question

activity 3
use traditional multiplication to find the product.
1.
\

$$\begin{array}{r} 68 \\\\ \\underline{\\times 56} \\end{array}$$

2.
\

$$\begin{array}{r} 309 \\\\ \\underline{\\times 42} \\end{array}$$

3.
\

$$\begin{array}{r} 601 \\\\ \\underline{\\times 23} \\end{array}$$

Explanation:

Problem 1: \(

$$\begin{array}{r} 68 \\ \times 56 \\ \hline \end{array}$$

\)

Step 1: Multiply by the ones digit (6)

Multiply 68 by 6: \( 68 \times 6 = 408 \)

Step 2: Multiply by the tens digit (5)

Multiply 68 by 50 (since 5 is in the tens place, it's 5×10): \( 68 \times 50 = 3400 \)

Step 3: Add the two results

Add 408 and 3400: \( 408 + 3400 = 3808 \)

Step 1: Multiply by the ones digit (2)

Multiply 309 by 2: \( 309 \times 2 = 618 \)

Step 2: Multiply by the tens digit (4)

Multiply 309 by 40 (since 4 is in the tens place, it's 4×10): \( 309 \times 40 = 12360 \)

Step 3: Add the two results

Add 618 and 12360: \( 618 + 12360 = 12978 \)

Step 1: Multiply by the ones digit (3)

Multiply 601 by 3: \( 601 \times 3 = 1803 \)

Step 2: Multiply by the tens digit (2)

Multiply 601 by 20 (since 2 is in the tens place, it's 2×10): \( 601 \times 20 = 12020 \)

Step 3: Add the two results

Add 1803 and 12020: \( 1803 + 12020 = 13823 \)

Answer:

3808

Problem 2: \(

$$\begin{array}{r} 309 \\ \times 42 \\ \hline \end{array}$$

\)