Question

add.
$(x^{2}+8xy - y^{2})+(5x^{2}-7xy + 23y^{2})$

$(x^{2}+8xy - y^{2})+(5x^{2}-7xy + 23y^{2})=square$ (do not factor.)

Explanation:

Step1: Combine like terms for \(x^2\)

\(x^2 + 5x^2 = (1 + 5)x^2 = 6x^2\)

Step2: Combine like terms for \(xy\)

\(8xy - 7xy = (8 - 7)xy = xy\)

Step3: Combine like terms for \(y^2\)

\(-y^2 + 23y^2 = (-1 + 23)y^2 = 22y^2\)

Step4: Combine all results

\(6x^2 + xy + 22y^2\)

Answer:

\(6x^2 + xy + 22y^2\)