Question

alda is making banners from a roll of paper that is 4.11 meters long. she will cut the paper into 3 equal lengths. she uses base - ten blocks to model how long each piece will be. complete the description of aldas error. alda should have put 1 one in each of the groups. 4 ones can be shared equally among 3 groups; 1 one in each group. she should have regrouped any left over ones and put 3? in each of the groups. then she should have regrouped the leftover tenths to get 7?. solve the problem. 4.11÷3 =

Explanation:

Step1: Divide the ones place

$4 \div 3 = 1$ with a remainder of $1$. The leftover 1 one is regrouped into 10 tenths, making the total tenths $10 + 1 = 11$ tenths.

Step2: Divide the tenths place

$11 \div 3 = 3$ with a remainder of $2$. The leftover 2 tenths are regrouped into 20 hundredths, making the total hundredths $20 + 1 = 21$ hundredths.

Step3: Divide the hundredths place

$21 \div 3 = 7$

Step4: Combine the results

Combine the quotient from each place: $1 + \frac{3}{10} + \frac{7}{100}$

Answer:

Aida should have put 1 one in each of the groups. 4 ones can be shared equally among 3 groups; 1 one in each group. She should have regrouped any left over ones and put 3 tenths in each of the groups. Then she should have regrouped the leftover tenths to get 7 hundredths.

$4.11 \div 3 = 1.37$