Question

alg1 8.4: graph f(x) = a(x - h)^2 + k, vertex f... jenifer youd in exercises 5 - 8, find the vertex and the axis of symmetry of the graph of the function. 5. f(x)=(x - 2)^2 + 0 vertex: (2,0) a.o.s.: x = 2 6. f(x)=-4(x + 8)^2 vertex: a.o.s.: copyright © big ideas learning, llc all rights reserved. algebra 1 263 student journal multiple - choice question what did you get for the vertex? (8,0) (-8,0) (-8,-4) (8,-4)

Explanation:

Step1: Recall vertex - form of quadratic function

The vertex - form of a quadratic function is $f(x)=a(x - h)^2 + k$, and the vertex is $(h,k)$.

Step2: Identify $h$ and $k$ for $f(x)=-4(x + 8)^2$

Rewrite $f(x)=-4(x + 8)^2$ as $f(x)=-4(x-(-8))^2+0$. Here, $h=-8$ and $k = 0$.

Answer:

B. (-8,0)