Question

algebra: concepts and connections - plc radical equations what is the value of q in the equation \\(\sqrt{4q - 2} = \sqrt{3q + 8}\\)? options: \\(\frac{10}{7}\\), 10, \\(-\frac{10}{7}\\), 6

Explanation:

Step1: Square both sides to eliminate radicals

$$(\sqrt{4q - 2})^2 = (\sqrt{3q + 8})^2$$
$$4q - 2 = 3q + 8$$

Step2: Isolate q on one side

$$4q - 3q = 8 + 2$$

Step3: Simplify to solve for q

$$q = 10$$

Answer:

10