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Question
algebra for exercises 20 - 22, use the figure at the right. 20. if (mangle cfd=12a + 45), find (a) so that (overrightarrow{fc}perpoverrightarrow{fd}).
Step1: Recall perpendicular - angle property
If $\overrightarrow{FC}\perp\overrightarrow{FD}$, then $m\angle CFD = 90^{\circ}$.
Step2: Set up the equation
Set $12a + 45=90$.
Step3: Solve for $a$
Subtract 45 from both sides: $12a=90 - 45$, so $12a = 45$. Then divide both sides by 12: $a=\frac{45}{12}=\frac{15}{4}=3.75$.
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$a = 3.75$