Question

angle relationships
boom cards
classify the angles
m∠fgh = 56°
find m∠kgf.
supplementary
complementary

Explanation:

Step1: Identify right angle at G

$\angle KGH = 90^\circ$

Step2: Split right angle into two parts

$\angle KGH = \angle KGF + \angle FGH$

Step3: Substitute known values

$90^\circ = \angle KGF + 56^\circ$

Step4: Solve for $\angle KGF$

$\angle KGF = 90^\circ - 56^\circ = 34^\circ$

Step5: Classify angle relationship

Complementary angles sum to $90^\circ$

Answer:

Angle classification: Complementary
$m\angle KGF = 34^\circ$