Question

your answer is incorrect. use synthetic division to find the quotient and remainder when $4x^4 + 11x^3 + 5x - 3$ is divided by $x + 3$ by completing the parts below. (a) complete this synthetic division table. \

$$\begin{array}{r|rrrrr} -3 & 4 & 11 & 0 & 5 & -3 \\\\ & & -12 & 3 & -9 & 12 \\\\ \\hline & 4 & -1 & 3 & -4 & 9 \\\\ \\end{array}$$

(b) write your answer in the following form: quotient + \frac{\text{remainder}}{x + 3}. \frac{4x^4 + 11x^3 + 5x - 3}{x + 3} = \square + \frac{\square}{x + 3}

Explanation:

Answer:

(a) The completed synthetic division table is already provided correctly as:

$$\begin{array}{r}-3\enclose{longdiv}{4\ \ 11\ \ \ 0\ \ \ 5\ \ -3} \\ \underline{-12\ \ \ 3\ \ -9\ \ 12} \\ 4\ \ -1\ \ \ 3\ \ -4\ \ \ 9 \end{array}$$

(b) $4x^3 - x^2 + 3x - 4$
$9$