Question

answer the questions below about the trains.
(a) what is the speed of each train?
train a: 80 $\frac{m}{s}$
train b: 65 $\frac{m}{s}$
train c: 55 $\frac{m}{s}$
(b) which train is the slowest?
train a train b train c
(c) how far does each train travel in 3 seconds?
train a: meters
train b: meters
train c: meters

Explanation:

Step1: Recall distance - speed formula

The formula for distance $d$ is $d = v\times t$, where $v$ is speed and $t$ is time.

Step2: Calculate distance for Train A

Given $v_A=80\frac{m}{s}$ and $t = 3s$. Using the formula $d_A=v_A\times t$, we have $d_A=80\times3 = 240$ meters.

Step3: Calculate distance for Train B

Given $v_B = 65\frac{m}{s}$ and $t = 3s$. Using the formula $d_B=v_B\times t$, we get $d_B=65\times3=195$ meters.

Step4: Calculate distance for Train C

Given $v_C = 55\frac{m}{s}$ and $t = 3s$. Using the formula $d_C=v_C\times t$, we obtain $d_C=55\times3 = 165$ meters.

Answer:

(a) Train A: $80\frac{m}{s}$, Train B: $65\frac{m}{s}$, Train C: $55\frac{m}{s}$
(b) Train C
(c) Train A: 240 meters, Train B: 195 meters, Train C: 165 meters