Question

i can apply the midsegment theorem to triangles.
solve the following for x and y.
** round answer to 2 decimal places if needed.

Explanation:

Step1: Use midsegment theorem for length

The midsegment of a triangle is half the length of the parallel side, so $x = 2 \times 8$

Step2: Solve for x

$x = 16$

Step3: Use corresponding angles for y

Parallel lines mean corresponding angles are equal: $7y + 5 = 4y$

Step4: Isolate y terms

$7y - 4y = -5$
$3y = -5$

Step5: Solve for y

$y = \frac{-5}{3} \approx -1.67$

Answer:

$x = 16$
$y = -1.67$