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Question
approximate \\(\sqrt{53}\\) by following the steps below. \\(\sqrt{53}\\) must lie between the whole numbers \\(\square\\) and \\(\square\\) answer attempt 1 out of 2 you must answer all questions above in order to submit. stuck?
Step1: Find perfect squares around 53
We know that $7^2 = 49$ and $8^2 = 64$.
Step2: Compare with 53
Since $49 < 53 < 64$, taking square roots (since square root is an increasing function), we get $\sqrt{49} < \sqrt{53} < \sqrt{64}$, which simplifies to $7 < \sqrt{53} < 8$.
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