Question

5.area of parallelogram: $36yd^{2}$area of trapezoid:area of composite figure:area: part 2show all work. be sure to include your units of measure. remember that area is measured in square units. missing dimensions are not measured in square units.6. find the height of a parallelogram with an area of 41 square meters and base 8.2 meters.answer:7. find the missing dimension of a triangle whose base is 4 inches and area is 22 square inches.answer:8. find the missing dimension of a triangle that had a height of 15ft and an area of 285 square feet.answer:9. a trapezoid has an area of 125 square millimeters. the bases are 13 millimeters and 12 millimeters. what is the height of the trapezoid?answer:10. a trapezoid has an area of 13.5 square inches. if the bases are 3 inches and 6 inches, what is the height of the trapezoid?answer:

Explanation:

For Question 5:

Step1: Calculate trapezoid area

The trapezoid has bases $11\ \text{yd}$ and $20\ \text{yd}$, height $8\ \text{yd}$. Area formula: $\frac{1}{2}(b_1+b_2)h$
$\frac{1}{2}(11+20)\times8 = \frac{1}{2}\times31\times8 = 124\ \text{yd}^2$

Step2: Calculate total composite area

Add parallelogram area ($36\ \text{yd}^2$) to trapezoid area.
$124 + 36 = 160$

Step1: Recall parallelogram area formula

$A = b\times h$, solve for $h$: $h=\frac{A}{b}$

Step2: Substitute values and calculate

$A=41\ \text{m}^2$, $b=8.2\ \text{m}$
$h=\frac{41}{8.2}=5$

Step1: Recall triangle area formula

$A=\frac{1}{2}\times b\times h$, solve for $h$: $h=\frac{2A}{b}$

Step2: Substitute values and calculate

$A=22\ \text{in}^2$, $b=4\ \text{in}$
$h=\frac{2\times22}{4}=11$

Answer:

Area of Trapezoid: $\boldsymbol{124\ \text{yd}^2}$
Area of Composite Figure: $\boldsymbol{160\ \text{yd}^2}$

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For Question 6: