Question

an area reserved for a parking lot is 80 feet long and 77 feet wide. the stalls of the lot are at 90° angles to two one - way aisles. each aisle is 80 feet by 10 feet. the three areas set aside for the parking spaces are congruent rectangles. each parking space will be 19 feet by 8 feet. what is the maximum number of parking spaces that will fit in the lot? 10 30 35 40

Explanation:

Step1: Calculate total width for parking - space areas

The total width of the parking - lot is 77 feet and there are two aisles each 10 feet wide. So the total width available for the three congruent parking - space rectangles is $77-(2\times10)=57$ feet. Then the width of each of the three congruent parking - space rectangles is $\frac{57}{3} = 19$ feet.

Step2: Calculate number of parking spaces in one rectangle

The length of each parking - space rectangle is 80 feet and the length of each parking space is 8 feet. The width of each parking - space rectangle is 19 feet and the width of each parking space is 19 feet. The number of parking spaces in one rectangle along the 80 - foot side is $\frac{80}{8}=10$.

Step3: Calculate total number of parking spaces

Since there are three congruent parking - space rectangles, the total number of parking spaces is $10\times3 = 30$.

Answer:

30