Question

area of a trapezoid, formula, a = ((b1 + b2)h)/2, a = ((4cm + 2cm))2cm/2, a = (6cm)(2cm)/2, a = 12cm²/2, a = 6cm²

Explanation:

Step1: Recall trapezoid - area formula

The formula for the area of a trapezoid is $A=\frac{(b_1 + b_2)h}{2}$, where $b_1$ and $b_2$ are the lengths of the bases and $h$ is the height.

Step2: Identify base - and height values

From the work shown, assume $b_1 = 4$ cm, $b_2 = 2$ cm, and $h = 2$ cm.

Step3: Substitute values into formula

$A=\frac{(4 + 2)\times2}{2}=\frac{6\times2}{2}$.

Step4: Calculate the area

$\frac{6\times2}{2}=6$ $cm^{2}$.

Answer:

$6$ $cm^{2}$