Question

1. the area of a trapezoid is found using: a = h(b1 + b2)/2 solve for h.

Explanation:

Step1: Multiply both sides by 2

To isolate the term with \( h \), we multiply both sides of the equation \( A=\frac{h(b_1 + b_2)}{2} \) by 2. This gives us \( 2A=h(b_1 + b_2) \).

Step2: Divide both sides by \( (b_1 + b_2) \)

Now, to solve for \( h \), we divide both sides of the equation \( 2A = h(b_1 + b_2) \) by \( (b_1 + b_2) \) (assuming \( b_1 + b_2
eq0 \)). So we get \( h=\frac{2A}{b_1 + b_2} \).

Answer:

\( h = \frac{2A}{b_1 + b_2} \)