Question

arrange the terms of the polynomial in descending powers of g.
$a^{2}g^{2}+a^{3}g - ag^{3}+14$
$a^{2}g^{2}+a^{3}g - ag^{3}+14=\square$

Explanation:

Step1: Identify powers of $g$

• Term $a^2g^2$: power of $g$ is 2
• Term $a^3g$: power of $g$ is 1
• Term $-ag^3$: power of $g$ is 3
• Term $14$: power of $g$ is 0

Step2: Order by descending powers

Arrange terms from highest to lowest power of $g$:
$-ag^3 + a^2g^2 + a^3g + 14$

Answer:

$-ag^3 + a^2g^2 + a^3g + 14$