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Question
assessment readiness
- find the standard form for the product of $(x^4 + 8)$ and $(x^2 - 2)$. choose true or false for each statement about the product.
a. it is a $4^\text{th}$ degree polynomial. $circ$ true $circ$ false
b. the constant term is $-16$. $circ$ true $circ$ false
c. it has 3 terms. $circ$ true $circ$ false
- multiply $(5x - 9)^2$. choose true or false for each statement about the product.
a. the coefficient of the $x$-term is $-45$. $circ$ true $circ$ false
b. the leading term is $25x^2$. $circ$ true $circ$ false
c. the constant term is $81$. $circ$ true $circ$ false
- find the product $(3x + 6)(3x - 6)$. show your work.
- find the product $(x + 10)(4x + 5)$. show your work.
- a rectangle has a length $(x + 6)$ m and a width of $7$ m. write expressions to represent the perimeter and area of the rectangle. explain how you determined your answers.
Question 3: Find the product \((3x + 6)(3x - 6)\)
Step1: Identify the formula
We can use the difference of squares formula \((a + b)(a - b)=a^2 - b^2\). Here, \(a = 3x\) and \(b = 6\).
Step2: Apply the formula
Substitute \(a = 3x\) and \(b = 6\) into the formula:
\((3x)^2-6^2\)
Step3: Simplify the terms
Calculate \((3x)^2 = 9x^2\) and \(6^2 = 36\), so we get \(9x^2 - 36\).
Question 4: Find the product \((x + 10)(4x + 5)\)
Step1: Use the distributive property (FOIL method)
Multiply the First terms: \(x\times4x = 4x^2\)
Multiply the Outer terms: \(x\times5 = 5x\)
Multiply the Inner terms: \(10\times4x = 40x\)
Multiply the Last terms: \(10\times5 = 50\)
Step2: Combine like terms
Add the outer and inner terms: \(5x+40x = 45x\)
Combine all terms: \(4x^2+45x + 50\)
Question 5: A rectangle has a length \((x + 6)\) m and a width of 7 m. Write expressions to represent the perimeter and area of the rectangle. Explain how you determined your answers.
For Perimeter:
Step1: Recall the perimeter formula for a rectangle
The formula for the perimeter \(P\) of a rectangle is \(P = 2\times(\text{length}+\text{width})\).
Step2: Substitute the values
Substitute length \(= x + 6\) and width \(= 7\) into the formula:
\(P=2\times((x + 6)+7)\)
Step3: Simplify the expression
First, simplify the expression inside the parentheses: \((x + 6)+7=x + 13\)
Then, multiply by 2: \(2\times(x + 13)=2x+26\)
For Area:
Step1: Recall the area formula for a rectangle
The formula for the area \(A\) of a rectangle is \(A=\text{length}\times\text{width}\).
Step2: Substitute the values
Substitute length \(= x + 6\) and width \(= 7\) into the formula:
\(A=(x + 6)\times7\)
Step3: Simplify the expression
Use the distributive property: \(7\times x+7\times6 = 7x + 42\)
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\(9x^2 - 36\)