Question

balance the nuclear reaction. supply 1 symbol and 2 numbers. 146 sm → 142 nd + a 62 60 c a = 1 b = 2 c = 3 the type of nuclear reaction is 4 and it emits 5 radiation. the reaction is not bombardment and so it is 6 and the half - life concept applies. a. 0 b. 1 c. -1 d. 2 e. 3 f. 4 g. 5 h. 6 i. radiation j. fusion k. none l. fission m. spontaneous n. electron capture o. bombardment p. α (alpha) q. β (beta) r. γ (gamma)

Explanation:

Step1: Balance mass - number

The mass - number on the left side of the nuclear reaction is 146 (for Sm). The mass - number of Nd is 142. So, the mass - number of particle A (B) is $146 - 142=4$.

Step2: Balance atomic - number

The atomic - number of Sm is 62 and that of Nd is 60. So, the atomic - number of particle A (C) is $62 - 60 = 2$. A particle with mass - number 4 and atomic - number 2 is an alpha particle, represented as $\alpha$.

Step3: Determine reaction type

Since the reaction is not a bombardment and involves the emission of a particle from a single nucleus, it is a spontaneous decay. The emission of an alpha particle means it is alpha decay.

Answer:

1. P. $\alpha$ (alpha)
2. 4
3. 2
4. L. fission
5. P. $\alpha$ (alpha)
6. M. spontaneous