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a ball rolls down a hill from a resting position (0m/s) and in 6 second…

Question

a ball rolls down a hill from a resting position (0m/s) and in 6 seconds it is rolling 18 meters per second (18m/s). what is the balls acceleration? * 10 points
no direction is given; acceleration cannot be calculated
24 meters per second squared
3 meters per second squared
12 meters per second

Explanation:

Step1: Identify the formula

The formula for acceleration is $a=\frac{v - u}{t}$, where $a$ is acceleration, $v$ is final - velocity, $u$ is initial - velocity, and $t$ is time.

Step2: Determine the values

Given $u = 0\ m/s$, $v=18\ m/s$, and $t = 6\ s$.

Step3: Substitute values into formula

$a=\frac{18 - 0}{6}=\frac{18}{6}=3\ m/s^{2}$

Answer:

C. 3 meters per second squared