Question

based on the free-body diagram, the net force acting on this firework is n. (diagram shows a vertical line with upward force ( f_{\text{up}} = 0.452 , \text{n} ) and downward force ( f_{\text{down}} = -0.452 , \text{n} ) or similar, with a firework image.)

Explanation:

Step1: Identify forces direction

Forces are opposite (up and down). Let upward be positive, so \( F_{up} = +0.452\,\text{N} \), \( F_{down} = -0.452\,\text{N} \).

Step2: Calculate net force

Net force \( F_{net} = F_{up} + F_{down} \). Substitute values: \( F_{net} = 0.452 + (-0.452) \).

Step3: Simplify the expression

\( 0.452 - 0.452 = 0 \).

Answer:

\( 0 \)